8x^2+34x-800=0

Solution for 8x^2+34x-800=0 equation:

8x^2+34x-800=0

a = 8; b = 34; c = -800;
Δ = b2-4ac
Δ = 342-4·8·(-800)
Δ = 26756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{26756}=\sqrt{4*6689}=\sqrt{4}*\sqrt{6689}=2\sqrt{6689}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-2\sqrt{6689}}{2*8}=\frac{-34-2\sqrt{6689}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+2\sqrt{6689}}{2*8}=\frac{-34+2\sqrt{6689}}{16}
$